Tupac's aunt wanted by the FBI,$2 000 000 reward

THE aunt of rap icon Tupac Shakur has become the first woman to land on the FBI's list of most wanted terrorists.

Cop killer Joanne Chesimard, 65 – who was also reportedly Tupac’s godmother – was convicted in 1977 of murdering a police officer, Trooper Werner Foerster, in New Jersey, US.

She was jailed but escaped in a dramatic break-out and later fled to Cuba.

The FBI have now doubled the reward for her capture, placing a $2million (£1.3m) bounty on her head.

Special agent Aaron Ford said: "Today, on the anniversary of Trooper Werner Foerster's death, we want the public to know that we will not rest until this fugitive is brought to justice".
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Tupac Shakur was one of the most successful rappers in the 1990s, whose career was cut short when he died at the age of 25 in a Las Vegas shooting.

In May 2, 1973, cops stopped former Black Liberation Army member Chesimard and two others at the New Jersey turnpike, for a driving violation before a gunfight broke out.

Both police officer Werner Foerster and one of Chesimard’s passengers were killed in the shooting.

Chesimard was arrested soon afterwards and convicted four years later of first-degree murder, assault and battery of a police officer, assault with a dangerous weapon, assault with intent to kill, illegal possession of a weapon and armed robbery.

She was handed life behind bars and began her sentence at a maximum security prison in West Virginia.

But after being transferred to a New Jersey minimum security prison, she escaped in 1979 with the help of three people visiting her, holding security guards at gunpoint and forcing them to open the prison gates.

The sun.